Generals 2001 II 6B

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The distance of closest approach is b=\frac{e^{2}}{T}, and the distance between particles is n − 1 / 3 The ratio is then:

\frac{b}{n^{-1/3}}=\frac{e^{2}}{n^{-1/3}T}=\frac{1}{4\pi n^{2/3}\lambda_{D}^{2}}


Where we have used \lambda_{D}^{2}=T/4\pi n_{e}e^{2}. The number of particles in a debye sphere is:

\Lambda=\frac{4}{3}\pi n\lambda_{D}^{3}


So that this ratio is expressable as:

\frac{b}{n^{-1/3}}=\left(4\pi\right)^{-1/3}3^{-2/3}\Lambda^{-2/3}\approx\frac{1}{4}\Lambda^{-2/3}
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