Dispersion relation

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The dispersion relation describes the relationship between the frequency ω and the wavenumber \mathbf{k} of a wave.

[edit] Zero order solution

In a homogenous unmagnetized cold plasma, the dispersion relation is given by:

\omega^{2}-\omega_{p}^{2}=c^2 k^2

Where ωp is the plasma frequency. For a full derivation, see Electromagnetic waves (dispersion).

[edit] Solution from Vlasov Equation

One can derive a dispersion relation by using a perturbation expansion of the distribution function and linearizing the collisionless Vlasov equation. This gives the result:

D(k,\omega)=1-\frac{4\pi e^2}{m_e} \int d^3v\,f_0\frac{1}{\left(\omega-kv_z\right)^2}=0

[edit] Derivation

We set f = f0 + f1, f_1\ll f_0, and assume E0 = v0 = B0 = 0 as well as v\ll c. This reduces the collisionless Vlasov equation to:

\frac{\partial f_1}{\partial t}  + \mathbf{v}_1 \cdot \frac{\partial f_1}{\partial \mathbf{x}}  - \frac{e}{m}\mathbf{E}\cdot \frac{\partial f_0}{\partial \mathbf{v}} =0

Then we assume the form f1˜exp(i[kz − ωt]), and use the electrostatic approximation, \mathbf{E}=-\nabla\phi. This gives:

-i\omega f_1 + v_z i k_z f_1  - \frac{e}{m}(-i k_z \phi) \frac{\partial f_0}{\partial v_z} =0

Solving for f1:

f_1 = -\frac{e k_z \phi}{m (\omega-v_z k_z)}  \frac{\partial f_0}{\partial v_z}

Poisson's equation with n_1 = \int d^3 v f_1 gives:

-\nabla^2 \phi = -4\pi e\int d^3 v f_1

Substituting in our expression for f1:

-k^2 \phi = 4\pi e\int d^3 v \frac{e k_z \phi}{m (\omega-v_z k_z)}  \frac{\partial f_0}{\partial v_z}

Cancelling terms and integrating by parts:

0 = 1 - \frac{4\pi e^2}{k_z m}\int d^3 v \frac{f_0}{(\omega-v_z k_z)^2}